﻿ C# - Return true if the array contains 10 or 20 twice

# C#: Check a given array of integers and return true if the array contains 10 or 20 twice

## C# Sharp Basic Algorithm: Exercise-100 with Solution

Write a C# Sharp program to check a given array of integers and return true if it contains 10 or 20 twice. The array length will be 0, 1, or 2.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

``````using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
class Program // Defining a class named 'Program'
{
static void Main(string[] args) // The entry point of the program
{
// Output the result of the 'test' method with different integer arrays as arguments
Console.WriteLine(test(new[] { 12, 20 })); // Calling test method with array [12, 20] and displaying the result
Console.WriteLine(test(new[] { 20, 20 })); // Calling test method with array [20, 20] and displaying the result
Console.WriteLine(test(new[] { 10, 10 })); // Calling test method with array [10, 10] and displaying the result
Console.WriteLine(test(new[] { 10 })); // Calling test method with array [10] and displaying the result
}

// Method to check if the input array has a length of 2 and contains either two 10s or two 20s
public static bool test(int[] nums)
{
// Checking if the array length is equal to 2
// and if the elements are either both 10 or both 20
return nums.Length == 2
&& ((nums[0] == 10 && nums[1] == 10)
|| (nums[0] == 20 && nums[1] == 20));
}
}
}
```
```

Sample Output:

```False
True
True
False
```

Flowchart:

C# Sharp Code Editor:

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