C#: Check whether a given number is an Armstrong number or not
C# Sharp For Loop: Exercise-29 with Solution
Write a C# Sharp Program to check whether a given number is an Armstrong number or not.

Sample Solution:-
C# Sharp Code:
/*When the sum of the cube of the individual digits of a number*/
/*is equal to that number, the number is called Armstrong number. For example 153.*/
/*Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/
using System;
public class Exercise29
{
public static void Main()
{
int num,r,sum=0,temp;
Console.Write("\n\n");
Console.Write("Check whether a given number is armstrong number or not:\n");
Console.Write("----------------------------------------------------------");
Console.Write("\n\n");
Console.Write("Input a number: ");
num = Convert.ToInt32(Console.ReadLine());
for(temp=num;num!=0;num=num/10){
r=num % 10;
sum=sum+(r*r*r);
}
if(sum==temp)
Console.Write("{0} is an Armstrong number.\n",temp);
else
Console.Write("{0} is not an Armstrong number.\n",temp);
}
}
Sample Output:
Check whether a given number is armstrong number or not: ---------------------------------------------------------- Input a number: 153 153 is an Armstrong number.
Flowchart:

C# Sharp Code Editor:
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Previous: Write a C# Sharp Program to find the perfect numbers within a given range of number.
Next: Write a C# Sharp Program to find the Armstrong number for a given range of number.
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