C#: Check whether a given number is an Armstrong number or not

C# Sharp For Loop: Exercise-29 with Solution

Write a C# Sharp Program to check whether a given number is an Armstrong number or not.

Sample Solution:-

C# Sharp Code:

/*When the sum of the cube of the individual digits of a number*/  
/*is equal to that number, the number is called Armstrong number. For example 153.*/  
/*Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/
using System;  
public class Exercise29
{  
    public static void Main()
{
    int num,r,sum=0,temp;
	
	
	Console.Write("\n\n");
    Console.Write("Check whether a given number is armstrong number or not:\n");
    Console.Write("----------------------------------------------------------");
    Console.Write("\n\n");  	

    Console.Write("Input  a number: ");
    num = Convert.ToInt32(Console.ReadLine());	

    for(temp=num;num!=0;num=num/10){
         r=num % 10;
         sum=sum+(r*r*r);
    }
    if(sum==temp)
         Console.Write("{0} is an Armstrong number.\n",temp);
    else
         Console.Write("{0} is not an Armstrong number.\n",temp);
    }
}

Sample Output:

Check whether a given number is armstrong number or not:                                                                                                       
----------------------------------------------------------                
Input  a number: 153                         
153 is an Armstrong number.   

Flowchart:

C# Sharp Code Editor:

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