C#: Find the Armstrong number for a given range of number

C# Sharp For Loop: Exercise-30 with Solution

Write a C# Sharp program to find the Armstrong number for a given range of numbers.

Sample Solution:-

C# Sharp Code:

/*When the sum of the cube of the individual digits of a number*/  
/*is equal to that number, the number is called Armstrong number. For example 153.*/  
/*Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/
using System;  
public class Exercise30  
{  
    public static void Main()
{
    int num,r,sum,temp;
    int stno,enno;
	
	Console.Write("\n\n");
    Console.Write("Find the Armstrong number for a given range of number:\n");
    Console.Write("--------------------------------------------------------");
    Console.Write("\n\n");  	

    Console.Write("Input starting number of range: ");
    stno= Convert.ToInt32(Console.ReadLine());	

    Console.Write("Input ending number of range : ");
    enno= Convert.ToInt32(Console.ReadLine());	

    Console.Write("Armstrong numbers in given range are: ");
    for(num=stno;num<=enno;num++){
         temp=num;
         sum = 0;

         while(temp!=0){
             r=temp % 10;
             temp=temp/10;
             sum=sum+(r*r*r);
         }
         if(sum==num)
             Console.Write("{0} ",num);
    }
        Console.Write("\n");
  }
}

Sample Output:

Find the Armstrong number for a given range of number:                                                                                                       
--------------------------------------------------------            
Input starting number of range: 1                                        
Input ending number of range : 500                                                                                                         
Armstrong numbers in given range are: 1 153 370 371 407 

Flowchart:

C# Sharp Code Editor:

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