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C# Sharp Exercises: Reverse the words of three or more lengths in a string

C# Sharp String: Exercise-57 with Solution

Write a C# Sharp program that takes a string and reverses the words of three or more lengths in a string. Return the updated string. As input characters, only letters and spaces are permitted.

Sample Data:
("The quick brown fox jumps over the lazy dog") -> "ehT kciuq nworb xof spmuj revo eht yzal god"
("Reverse the words of three or more") -> "esreveR eht sdrow of eerht or erom"
("ABcDef") -> "feDcBA"

Sample Solution:

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {
            // Declare and initialize a string variable
            string text = "The quick brown fox jumps over the lazy dog";

            // Display the original string
            Console.WriteLine("Original strings: " + text);

            // Display the action about to be performed
            Console.WriteLine("\nReverse the words of three or more lengths of the said string:");

            // Invoke the 'test' method and display the modified string
            Console.WriteLine(test(text));
        }

        // Define a method 'test' that takes a string argument 'text' and returns a modified string
        public static string test(string text)
        {
            // Split the input text into words, check if the word length is three or more
            // If the length is three or more, reverse the characters of the word; otherwise, keep the word as it is
            return string.Join(" ", text.Split(' ').Select(x => x.Length >= 3 ? new string(x.Reverse().ToArray()) : new string(x.ToArray())));
        }
    }
}

Sample Output:

Original strings: The quick brown fox jumps over the lazy dog

Reverse the words of three or more lengths of the said string:
ehT kciuq nworb xof spmuj revo eht yzal god

Flowchart :

Flowchart: C# Sharp Exercises - Find the longest common ending between two given strings.

C# Sharp Code Editor:

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Previous: Find the longest common ending between two strings.
Next: Check if a string is an anagram of another given string.

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