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Java Array Exercises: Find the second largest element in an array

Java Array: Exercise-17 with Solution

Write a Java program to find the second largest element in an array.

Pictorial Presentation:

Java Array Exercises: Find the second largest element in an array

Sample Solution:

Java Code :

import java.util.Arrays;
public class Main {
public static void main(String[] args) {
int[] my_array = {
            10789, 2035, 1899, 1456, 2013, 
            1458, 2458, 1254, 1472, 2365, 
            1456, 2165, 1457, 2456};
System.out.println("Original numeric array : "+Arrays.toString(my_array));            
Arrays.sort(my_array);
int index = my_array.length-1;
while(my_array[index]==my_array[my_array.length-1]){
index--;
}
System.out.println("Second largest value: " + my_array[index]);
}
}

Sample Output:

Original numeric array : [10789, 2035, 1899, 1456, 2013, 1458, 2458, 1254, 1472, 2365, 1456, 2165, 1457, 2456]
Second largest value: 2458

Flowchart:

Flowchart: Java exercises: Find the second largest element in an array

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Java Code Editor:

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY