﻿ Java - Find the second smallest element in an array

# Java: Find the second smallest element in an array

## Java Array: Exercise-18 with Solution

Write a Java program to find the second smallest element in an array.

Pictorial Presentation:

Sample Solution:

Java Code :

``````// Import the necessary Java utilities package.
import java.util.Arrays;

// Define a class named Exercise18.
public class Exercise18 {
// The main method where the program execution starts.
public static void main(String[] args) {
// Create an integer array with numeric values.
int[] my_array = {-1, 4, 0, 2, 7, -3};

// Print the original numeric array.
System.out.println("Original numeric array : " + Arrays.toString(my_array));

// Initialize variables to find the minimum and second minimum values.
int min = Integer.MAX_VALUE;
int second_min = Integer.MAX_VALUE;

// Iterate through the array to find the second lowest number.
for (int i = 0; i < my_array.length; i++) {
if (my_array[i] == min) {
// If the current element equals the minimum, update the second minimum.
second_min = min;
} else if (my_array[i] < min) {
// If the current element is less than the minimum, update both minimum and second minimum.
second_min = min;
min = my_array[i];
} else if (my_array[i] < second_min) {
// If the current element is less than the second minimum, update the second minimum.
second_min = my_array[i];
}
}

// Print the second lowest number found.
System.out.println("Second lowest number is : " + second_min);
}
}
```
```

Sample Output:

```Original numeric array : [-1, 4, 0, 2, 7, -3]
Second lowest number is : -1
```

Flowchart:

Java Code Editor:

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