w3resource

Java Array Exercises: Find the number of even and odd integers in a given array of integers

Java Array: Exercise-27 with Solution

Write a Java program to find the number of even and odd integers in a given array of integers.

Pictorial Presentation:

Java Array Exercises: Find the number of even and odd integers in a given array of integers

Sample Solution:

Java Code:

import java.util.Arrays; 
 public class Exercise27 {
 public static void main(String[] args)
 {
    int[] array_nums = {5, 7, 2, 4, 9};
	System.out.println("Original Array: "+Arrays.toString(array_nums)); 
	int ctr = 0;
	for(int i = 0; i < array_nums.length; i++)
	{
		if(array_nums[i] % 2 == 0)
			ctr++;
	}
	System.out.println("Number of even numbers : "+ctr);
	System.out.println("Number of odd numbers  : "+(array_nums.length-ctr));
 }
}

Sample Output:

                                                                              
Original Array: [5, 7, 2, 4, 9]                                        
Number of even numbers : 2                                             
Number of odd numbers  : 3 

Flowchart:

Flowchart: Java exercises: Find the number of even and odd integers in a given array of integers

Visualize Java code execution (Python Tutor):


Java Code Editor:

Improve this sample solution and post your code through Disqus

Previous: Write a Java program to move all 0's to the end of an array.
Next: Write a Java program to get the difference between the largest and smallest values in an array of integers.

What is the difficulty level of this exercise?



Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY