Java Array Exercises: Cyclically rotate a given array clockwise by one

Java Array: Exercise-45 with Solution

Write a Java program to cyclically rotate a given array clockwise by one.

Pictorial Presentation:

Java Array Exercises: Cyclically rotate a given array clockwise by one

Sample Solution:

Java Code:

import java.util.Arrays;
 public class Main
    static int arra[] = new int[]{10, 20, 30, 40, 50, 60};
    static void rotate_array()
       int a = arra[arra.length-1], i;
       for (i = arra.length-1; i > 0; i--)
          arra[i] = arra[i-1];
       arra[0] = a;
   public static void main(String[] args) 
        System.out.println("Original arraay:");
        System.out.println("Rotated arraay:");

Sample Output:

Original arraay:
[10, 20, 30, 40, 50, 60]
Rotated arraay:
[60, 10, 20, 30, 40, 50]


Flowchart: Cyclically rotate a given array clockwise by one

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Next: Write a Java program to check whether there is a pair with a specified sum of a given sorted and rotated array.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY