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Java Array Exercises: Test if an array contains a specific value

Java Array: Exercise-5 with Solution

Write a Java program to test if an array contains a specific value.

Pictorial Presentation:

Java Array Exercises: Test if an array contains a specific value

Sample Solution:

Java Code:

public class Exercise5 {
  public static boolean contains(int[] arr, int item) {
      for (int n : arr) {
         if (item == n) {
            return true;
         }
      }
      return false;
   }
   public static void main(String[] args) {
          int[] my_array1 = {
            1789, 2035, 1899, 1456, 2013, 
            1458, 2458, 1254, 1472, 2365, 
            1456, 2265, 1457, 2456};
      System.out.println(contains(my_array1, 2013));
      System.out.println(contains(my_array1, 2015));
   }
}

Sample Output: 

true                                                                                                       
false

Flowchart:

Flowchart: Java exercises: Test if an array contains a specific value

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Java Code Editor:

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Next: Write a Java program to find the index of an array element.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY