Java: Find the index of an array element
Java Array: Exercise-6 with Solution
Write a Java program to find the index of an array element.
Pictorial Presentation:

Sample Solution:
Java Code:
// Define a class named Exercise6.
public class Exercise6 {
// Define a method 'findIndex' that searches for an integer 't' in an integer array 'my_array'.
public static int findIndex(int[] my_array, int t) {
// Check if the array is null and return -1 if it is.
if (my_array == null)
return -1;
// Get the length of the array.
int len = my_array.length;
int i = 0;
// Iterate through the elements in the array.
while (i < len) {
// Check if the current element is equal to 't' and return its index if found.
if (my_array[i] == t)
return i;
else
i = i + 1;
}
// If 't' is not found in the array, return -1.
return -1;
}
// The main method where the program execution starts.
public static void main(String[] args) {
// Declare an integer array 'my_array' and initialize it with values.
int[] my_array = {25, 14, 56, 15, 36, 56, 77, 18, 29, 49};
// Find and print the index position of value 25 in the array.
System.out.println("Index position of 25 is: " + findIndex(my_array, 25));
// Find and print the index position of value 77 in the array.
System.out.println("Index position of 77 is: " + findIndex(my_array, 77));
}
}
Sample Output:
Index position of 25 is: 0 Index position of 77 is: 6
Flowchart:

Java Code Editor:
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Next: Write a Java program to remove a specific element from an array.
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