Java: Check if a sub-array is formed by consecutive integers from a given array of integers

Java Array: Exercise-57 with Solution

Write a Java program to check if a sub-array is formed by consecutive integers from a given array of integers.

Example:
Input :
nums = { 2, 5, 0, 2, 1, 4, 3, 6, 1, 0 }
Output:
The largest sub-array is [1, 7]
Elements of the sub-array: 5 0 2 1 4 3 6

Sample Solution:

Java Code:

import java.lang.Math;
import java.util.Arrays;
class solution
{
	static boolean is_consecutive(int nums[], int i, int j, int min, int max)
	{
		if (max - min != j - i) {
			return false;
		}

		boolean check[] = new boolean[j - i + 1];

		for (int k = i; k <= j; k++)
		{
			if (check[nums[k] - min]) {
				return false;
			}

			check[nums[k] - min] = true;
		}
	
		return true;
	}
	
	public static void find_Max_SubArray(int[] nums)
	 {
		int len = 1;
		int start = 0, end = 0;

		for (int i = 0; i < nums.length - 1; i++)
		{
			int min_val = nums[i], max_val = nums[i];
	
			for (int j = i + 1; j < nums.length; j++)
			{
				min_val = Math.min(min_val, nums[j]);
				max_val = Math.max(max_val, nums[j]);
	
				if (is_consecutive(nums, i, j, min_val, max_val))
				{
					if (len < max_val - min_val + 1)
					{
						len = max_val - min_val + 1;
						start = i;
						end = j;
					}
				}
			}
		}
	
		System.out.println("The largest sub-array is [" + start + ", "
							+ end + "]");
		System.out.print("Elements of the sub-array: ");
	    for (int x = start; x <= end; x++)
	     {
			
		  System.out.print(nums[x]+" ");			
		 }	
	}

	public static void main (String[] args)
	{
		int[] nums = { 2, 5, 0, 2, 1, 4, 3, 6, 1, 0 };
        System.out.println("Original array: "+Arrays.toString(nums)); 
		find_Max_SubArray(nums);
	}
} 

Sample Output:

                                                                              
Original array: [2, 5, 0, 2, 1, 4, 3, 6, 1, 0]
The largest sub-array is [1, 7]
Elements of the sub-array: 5 0 2 1 4 3 6 

Flowchart:

Java Code Editor:

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