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Java Array Exercises: Find and print one continuous subarray to sort an entire array

Java Array: Exercise-72 with Solution

Write a Java program to find and print one continuous subarray (from a given array of integers) that if you only sort the said subarray in ascending order then the entire array will be sorted in ascending order.

Example:
Input :
nums1 = {1, 2, 3, 0, 4, 6}
nums2 = { 1, 3, 2, 7, 5, 6, 4, 8}
Output:
Continuous subarray:
1 2 3 0
Continuous subarray:
3 2 7 5 6 4

Sample Solution:

Java Code:

import java.util.Arrays;
public class solution {
public static int[] findUnsortedSubarray(int[] nums) {
			int[] result = new int[3];
            int n = nums.length;
            int start = -1;
            int end = -2;
            int min = nums[n - 1];
            int max = nums[0];
            for (int i = 1; i < n; i++) {
                max = Math.max(max, nums[i]);
                min = Math.min(min, nums[n - 1 - i]);
                if (nums[i] < max) {
                    end = i;
                }
                if (nums[n - 1 - i] > min) {
                    start = n - 1 - i;
                }
            }
           		result[0] = start;
		    result[1] = end;

			return result;
        }
    
  public static void main(String[] args)
  {
    int[] nums1 = {1, 2, 3, 0, 4, 6};
	System.out.printf("\nOriginal array: "+Arrays.toString(nums1));	

	int[] result1 = findUnsortedSubarray(nums1);
	System.out.printf("\nContinuous subarray:\n");
	for(int i=result1[0]; i<=result1[1]; i++){
        System.out.print(nums1[i] +" ");
        }
	
	int[] nums2 = { 1, 3, 2, 7, 5, 6, 4, 8};
	System.out.printf("\n\nOriginal array: "+Arrays.toString(nums2));	
    System.out.printf("\nContinuous subarray:\n"); 
	int[] result2 = findUnsortedSubarray(nums2);
	
	for(int i=result2[0]; i<=result2[1]; i++){
        System.out.print(nums2[i] +" ");
        }
   }  
}

Sample Output:

Original array: [1, 2, 3, 0, 4, 6]
Continuous subarray:
1 2 3 0 

Original array: [1, 3, 2, 7, 5, 6, 4, 8]
Continuous subarray:
3 2 7 5 6 4 

Flowchart:

Flowchart: Find and print one continuous subarray to sort an entire array.

Java Code Editor:

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Previous: Write a Java program to form the largest number from a given list of non negative integers.
Next: Write a Java program to sort a given array of distinct integers where all its numbers are sorted except two numbers.

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY