﻿ Java - Count 2 elements of 2 arrays with same length

# Java: Count the two elements of two given arrays of integers with same length, differ by 1 or less

## Java Basic: Exercise-100 with Solution

Write a Java program to count the elements that differ by 1 or less between two given arrays of integers with the same length.

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.*;

public class Exercise100 {
public static void main(String[] args) {
int[] array_nums1 = {10, 11, 10, 20, 43, 20, 50};
int[] array_nums2 = {10, 13, 11, 20, 44, 30, 50};
System.out.println("Array1: "+Arrays.toString(array_nums1));
System.out.println("Array2: "+Arrays.toString(array_nums2));

int ctr = 0; // Initialize a counter to keep track of the number of elements

// Iterate through the arrays to compare elements at the same index
for (int i = 0; i < array_nums1.length; i++) {
// Check if the absolute difference between elements is less than or equal to 1
// and the elements are not equal
if (Math.abs(array_nums1[i] - array_nums2[i]) <= 1 && array_nums1[i] != array_nums2[i]) {
ctr++; // If the condition is met, increment the counter
}
}

System.out.printf("Number of elements: "+ctr); // Print the number of elements meeting the condition
System.out.printf("\n");
}
}
```
```

Sample Output:

```Array1: [10, 11, 10, 20, 43, 20, 50]
Array2: [10, 13, 11, 20, 44, 30, 50]
Number of elements: 2
```

Flowchart: Java Code Editor:

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