Java: Count the two elements of two given arrays of integers with same length, differ by 1 or less
Java Basic: Exercise-100 with Solution
Write a Java program to count the elements that differ by 1 or less between two given arrays of integers with the same length.
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.*;
public class Exercise100 {
public static void main(String[] args) {
int[] array_nums1 = {10, 11, 10, 20, 43, 20, 50};
int[] array_nums2 = {10, 13, 11, 20, 44, 30, 50};
System.out.println("Array1: "+Arrays.toString(array_nums1));
System.out.println("Array2: "+Arrays.toString(array_nums2));
int ctr = 0; // Initialize a counter to keep track of the number of elements
// Iterate through the arrays to compare elements at the same index
for (int i = 0; i < array_nums1.length; i++) {
// Check if the absolute difference between elements is less than or equal to 1
// and the elements are not equal
if (Math.abs(array_nums1[i] - array_nums2[i]) <= 1 && array_nums1[i] != array_nums2[i]) {
ctr++; // If the condition is met, increment the counter
}
}
System.out.printf("Number of elements: "+ctr); // Print the number of elements meeting the condition
System.out.printf("\n");
}
}
Sample Output:
Array1: [10, 11, 10, 20, 43, 20, 50] Array2: [10, 13, 11, 20, 44, 30, 50] Number of elements: 2
Flowchart:
Java Code Editor:
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