w3resource

Java Exercises: Check if the number of 10 is greater than number to 20's in a given array of integers

Java Basic: Exercise-101 with Solution

Write a Java program to check if the number of 10 is greater than number to 20's in a given array of integers.

Pictorial Presentation:

Java Basic Exercises: Check if the number of 10 is greater than number to 20's in a given array of integers

Sample Solution:

Java Code:

import java.util.*; 
import java.io.*; 
 public class Exercise101 {
 public static void main(String[] args)
 {
	int[] array_nums = {10, 11, 10, 30, 45, 20, 33, 53};
    int result = 0; 
	System.out.println("Original Array: "+Arrays.toString(array_nums)); 
    
	int ctr1 = 0;
    int ctr2 = 0;
      
    for(int i = 0; i < array_nums.length; i++) {
        if(array_nums[i] == 10)
            ctr1++;
                        
        if(array_nums[i] == 20)
            ctr2++;
    }                                      
    System.out.printf(String.valueOf(ctr1 > ctr2));
	System.out.printf("\n");
  }
}

Sample Output:

Original Array: [10, 11, 10, 30, 45, 20, 33, 53]                       
true

Flowchart:

Flowchart: Java exercises: Check if the number of 10 is greater than number to 20's in a given array of integers

Java Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a Java program to count the two elements of two given arrays of integers with same length, differ by 1 or less.
Next: Write a Java program to check if a specified array of integers contains 10's or 30's.

What is the difficulty level of this exercise?



Java: Tips of the Day

Try and catch:

Java is excellent at catching errors, but it can only recover gracefully if you tell it what to do. The cascading hierarchy of attempting to perform an action in Java starts with try, falls back to catch, and ends with finally. Should the try clause fail, then catch is invoked, and in the end, there's always finally to perform some sensible action regardless of the results. Here's an example:

try {
        cmd = parser.parse(opt, args); 
       
        if(cmd.hasOption("help")) {
                HelpFormatter helper = new HelpFormatter();
                helper.printHelp("Hello ", opt);
                System.exit(0);
                }
        else {
                if(cmd.hasOption("shell") || cmd.hasOption("s")) {
                String target = cmd.getOptionValue("tgt");
                } // else
        } // fi
} catch (ParseException err) {
        System.out.println(err);
        System.exit(1);
        } //catch
        finally {
                new Hello().helloWorld(opt);
        } //finally
} //try

It's a robust system that attempts to avoid irrecoverable errors or, at least, to provide you with the option to give useful feedback to the user. Use it often, and your users will thank you!

Ref: https://red.ht/3EZc9OC