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Java Exercises: Create a new string taking first and last characters from two given strings

Java Basic: Exercise-73 with Solution

Write a Java program to create a new string taking first and last characters from two given strings. If the length of either string is 0 use "#" for missing character.

Pictorial Presentation:

Java Basic Exercises: Create a new string taking first and last characters from two given strings

Sample Solution:

Java Code:

import java.lang.*;
 public class Exercise73 {
 public static void main(String[] args)
 {
    String str1 = "Python"; 
	String str2 = ""; 
	
	int length2 = str2.length();
	String result = "";
	result += (str1.length() >= 1) ? str1.charAt(0) : '#';
	result += (length2 >= 1) ? str2.charAt(length2-1) : '#';
	System.out.println(result);
 }
}

Sample Output: 

P#

Flowchart:

Flowchart: Java exercises: Create a new string taking first and last characters from two given strings

Java Code Editor:

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Next:Write a Java program to test if 10 appears as either the first or last element of an array of integers.

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Java: Tips of the Day

Execution of console commands:

Java allows you to execute console commands directly from code using a class Runtime. It is very important not to forget about exception handling.

For example, let's try to open a PDF file through a Java terminal:

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
  
public class ShellCommandExec {
  
  public static void main(String[] args) {
    String gnomeOpenCommand = "gnome-open //home//user//Documents//MyDoc.pdf";
  
    try {
      Runtime rt = Runtime.getRuntime();
      Process processObj = rt.exec(gnomeOpenCommand);
  
      InputStream stdin = processObj.getErrorStream();
      InputStreamReader isr = new InputStreamReader(stdin);
      BufferedReader br = new BufferedReader(isr);
  
      String myoutput = "";
  
      while ((myoutput=br.readLine()) != null) {
        myoutput = myoutput+"\n";
      }
      System.out.println(myoutput);
    }
    catch (Exception e) {
      e.printStackTrace();
    }
  }
}