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Java Exercises: Check if an array of integers contains a specified number next to each other or there are two same specified numbers separated by one element

Java Basic: Exercise-97 with Solution

Write a Java program to check if an array of integers contains a specified number next to each other or there are two same specified numbers separated by one element.

Pictorial Presentation:

Java Basic Exercises: Check if an array of integers contains a specified number next to each other or there are two same specified numbers separated by one element

Sample Solution:

Java Code:

import java.util.*; 
import java.io.*; 
 public class Exercise97 {
 public static void main(String[] args)
 {
	  int[] array_nums = {10, 20, 10, 50, 20, 13, 50};
	//int[] array_nums = {10, 10, 50, 50, 20, 13, 50};
      boolean testd = false;
	  int result=0;
	  int x = 10;
	      
	for(int i = 0; i < array_nums.length - 1; i++) {
        if(array_nums[i] == x && array_nums[i+1] == x)
            {
         System.out.printf( String.valueOf(true));	
         result = 1 ;
		}
                  
        if(i <= array_nums.length - 3 && array_nums[i] == x && array_nums[i+2] == x)
           {
         System.out.printf( String.valueOf(true));	
         result = 1 ;
		}
    }
	
	 if (result==0)                             
	   {	 
         System.out.printf( String.valueOf(false));
	    }
		System.out.printf("\n");
    }
}

Sample Output: 

true

Flowchart:

Flowchart: Java exercises: Check if an array of integers contains a specified number next to each other or there are two same specified numbers separated by one element

Java Code Editor:

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Previous: Write a Java program to check if there is a 10 in a given array of integers with a 20 somewhere later in the array.
Next: Write a Java program to check if the value 20 appears three times and no 20’s are next to each other in an given array of integers.

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Java: Tips of the Day

Execution of console commands:

Java allows you to execute console commands directly from code using a class Runtime. It is very important not to forget about exception handling.

For example, let's try to open a PDF file through a Java terminal:

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
  
public class ShellCommandExec {
  
  public static void main(String[] args) {
    String gnomeOpenCommand = "gnome-open //home//user//Documents//MyDoc.pdf";
  
    try {
      Runtime rt = Runtime.getRuntime();
      Process processObj = rt.exec(gnomeOpenCommand);
  
      InputStream stdin = processObj.getErrorStream();
      InputStreamReader isr = new InputStreamReader(stdin);
      BufferedReader br = new BufferedReader(isr);
  
      String myoutput = "";
  
      while ((myoutput=br.readLine()) != null) {
        myoutput = myoutput+"\n";
      }
      System.out.println(myoutput);
    }
    catch (Exception e) {
      e.printStackTrace();
    }
  }
}