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Java Exercises: Check if the value 20 appears three times and no 20's are next to each other in a given array of integers

Java Basic: Exercise-98 with Solution

Write a Java program to check if the value 20 appears three times and no 20’s are next to each other in a given array of integers.

Pictorial Presentation:

Java Basic Exercises: Check if the value 20 appears three times and no 20's are next to each other in a given array of integers

Sample Solution:

Java Code:

import java.util.*; 
import java.io.*; 
 public class Exercise98 {
 public static void main(String[] args)
 {
	int[] array_nums = {10, 20, 10, 20, 40, 13, 20};
		
	int count = 0, result =0;
    
    if(array_nums.length >= 1 && array_nums[0] == 20)
        count++;

    for(int i = 1; i < array_nums.length; i++) {
        if(array_nums[i - 1] == 20 && array_nums[i] == 20)
		{
         System.out.printf( String.valueOf(false));	
         result = 1;
		}                   
        if(array_nums[i] == 20)
            count++;
    }
                                          
    if (result==0)
 	  {
     	 System.out.printf( String.valueOf(count == 3));	         
	  }	
	  System.out.printf("\n");	
    }
}

Sample Output:

true

Flowchart:

Flowchart: Java exercises: Check if the value 20 appears three times and no 20's are next to each other in a given array of integers

Java Code Editor:

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Previous: Write a Java program to check if an array of integers contains a specified number next to each other or there are two same specified numbers separated by one element.
Next: Write a Java program to check if a specified number appears in every pair of adjacent element of a given array of integers.

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Java: Tips of the Day

countOccurrences

Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)
            .count();
}

Ref: https://bit.ly/3kCAgLb