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Java: Get the element in a tree set which is greater than or equal to the given element

Java Collection, TreeSet Exercises: Exercise-10 with Solution

Write a Java program to get the element in a tree set which is greater than or equal to the given element.

Sample Solution:

Java Code:

import java.util.TreeSet;
import java.util.Iterator;

  public class Exercise10 {
  public static void main(String[] args) {
 // creating TreeSet 
   TreeSet <Integer>tree_num = new TreeSet<Integer>();
   TreeSet <Integer>treeheadset = new TreeSet<Integer>();
     
   // Add numbers in the tree
   tree_num.add(10);
   tree_num.add(22);
   tree_num.add(36);
   tree_num.add(25);
   tree_num.add(16);
   tree_num.add(70);
   tree_num.add(82);
   tree_num.add(89);
   tree_num.add(14);
   
   System.out.println("Greater than or equal to 86 : "+tree_num.ceiling(86));
   System.out.println("Greater than or equal to 29 : "+tree_num.ceiling(29));
   }    
}

Sample Output:

Greater than or equal to 86 : 89                                       
Greater than or equal to 29 : 36

Flowchart:

Flowchart: Get the element in a tree set which is greater than or equal to the given element

Java Code Editor:

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Java: Tips of the Day

Oddness Check

Is it possible to use this code to accurately determine the odd number?

public boolean oddOrNot(int num) {
  return num % 2 == 1;
}

I hope you noticed a trick. If we decide to check a negative odd number in such a way (-5, for example), the remainder of the division will not be equal to one (what does it mean?) Therefore, use a more accurate method:

public boolean oddOrNot(int num) {
  return (num & 1) != 0;
}

It not only solves the problem of negative numbers, but also works more productively than its predecessor. Arithmetic and logical operations are performed much faster than multiplication and division.

Ref: https://bit.ly/3giyonA

 





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