Java: Display n terms of natural numbers and their sum
Java Conditional Statement: Exercise-11 with Solution
Write a Java program to display n terms of natural numbers and their sum.
Test Data
Input number: 7
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise11 {
public static void main(String[] args)
{
int i, n, sum=0;
{
Scanner in = new Scanner(System.in);
System.out.print("Input number: ");
n = in.nextInt();
}
System.out.println("The first n natural numbers are : "+n);
for(i=1;i<=n;i++)
{
System.out.println(i);
sum+=i;
}
System.out.println("The Sum of Natural Number upto "+n+ " terms : " +sum);
}
}
Sample Output:
Input number: 7 The first n natural numbers are : 7 1 2 3 4 5 6 7 The Sum of Natural Number upto n terms : 28
Flowchart:

Java Code Editor:
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Previous: Write a program in Java to display the first 10 natural numbers.
Next: Write a program in Java to input 5 numbers from keyboard and find their sum and average.
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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