﻿ Java - Display n terms of natural numbers and their sum

# Java: Display n terms of natural numbers and their sum

## Java Conditional Statement: Exercise-11 with Solution

Write a Java program to display n terms of natural numbers and their sum.

Test Data
Input number: 7

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.Scanner;
public class Exercise11 {

public static void main(String[] args)

{
int i, n, sum=0;
{
Scanner in = new Scanner(System.in);
System.out.print("Input number: ");
n = in.nextInt();
}
System.out.println("The first n natural numbers are : "+n);

for(i=1;i<=n;i++)
{
System.out.println(i);
sum+=i;
}
System.out.println("The Sum of Natural Number upto "+n+ " terms : " +sum);

}
}
```
```

Sample Output:

```Input number: 7
The first n natural numbers are : 7
1
2
3
4
5
6
7
The Sum of Natural Number upto n terms : 28
```

Flowchart: Java Code Editor:

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﻿

## Java: Tips of the Day

IsPowerOfTwo

Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

```public static boolean isPowerOfTwo(final int value) {
return value > 0 && ((value & (~value + 1)) == value);
}
```

Ref: https://bit.ly/3sA5d4I

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