﻿ Java - Display the cube of the number upto given an integer

# Java: Display the cube of the number upto given an integer

## Java Conditional Statement: Exercise-13 with Solution

Write a Java program to display the cube of the given number up to an integer.

Test Data
Input number of terms : 4

Pictorial Presentation:

Sample Solution:

Java Code:

``````import java.util.Scanner;
public class Exercise13 {

public static void main(String[] args)

{
int i,n;

System.out.print("Input number of terms : ");
Scanner in = new Scanner(System.in);
n = in.nextInt();

for(i=1;i<=n;i++)
{
System.out.println("Number is : " +i+" and cube of " +i+" is : "+(i*i*i));
}
}
}
```
```

Sample Output:

```Input number of terms : 4
Number is : 1 and cube of 1 is : 1
Number is : 2 and cube of 2 is : 8
Number is : 3 and cube of 3 is : 27
Number is : 4 and cube of 4 is : 64
```

Flowchart:

Java Code Editor:

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﻿

## Java: Tips of the Day

IsPowerOfTwo

Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

```public static boolean isPowerOfTwo(final int value) {
return value > 0 && ((value & (~value + 1)) == value);
}
```

Ref: https://bit.ly/3sA5d4I

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