﻿ Java - Display n terms of odd natural number and their sum

# Java: Display the n terms of odd natural number and their sum

## Java Conditional Statement: Exercise-15 with Solution

Write a Java program that displays the sum of n odd natural numbers.

Test Data
Input number of terms is: 5

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.Scanner;
public class Exercise15 {

public static void main(String[] args)

{
int i,n,sum=0;

System.out.print("Input number of terms is: ");
{
Scanner in = new Scanner(System.in);
n = in.nextInt();
System.out.println ("\nThe odd numbers are :");
for(i=1;i<=n;i++)

{
System.out.println (2*i-1);
sum+=2*i-1;
}
System.out.println ("The Sum of odd Natural Number upto " +n+" terms is: " +sum);

}
}
}
```
```

Sample Output:

```Input number of terms is: 5
The odd numbers are :
1
3
5
7
9
The Sum of odd Natural Number upto 5 terms is: 25
```

Flowchart: Java Code Editor:

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﻿

## Java: Tips of the Day

IsPowerOfTwo

Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

```public static boolean isPowerOfTwo(final int value) {
return value > 0 && ((value & (~value + 1)) == value);
}
```

Ref: https://bit.ly/3sA5d4I

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