Java: Solve quadratic equations
Java Conditional Statement: Exercise-2 with Solution
Write a Java program to solve quadratic equations (use if, else if and else).
Test Data
Input a: 1
Input b: 5
Input c: 1
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise2 {
public static void main(String[] Strings) {
Scanner input = new Scanner(System.in);
System.out.print("Input a: ");
double a = input.nextDouble();
System.out.print("Input b: ");
double b = input.nextDouble();
System.out.print("Input c: ");
double c = input.nextDouble();
double result = b * b - 4.0 * a * c;
if (result > 0.0) {
double r1 = (-b + Math.pow(result, 0.5)) / (2.0 * a);
double r2 = (-b - Math.pow(result, 0.5)) / (2.0 * a);
System.out.println("The roots are " + r1 + " and " + r2);
} else if (result == 0.0) {
double r1 = -b / (2.0 * a);
System.out.println("The root is " + r1);
} else {
System.out.println("The equation has no real roots.");
}
}
}
Sample Output:
Input a: 1 Input b: 5 Input c: 2 The roots are -0.4384471871911697 and -4.561552812808831
Flowchart:

Java Code Editor:
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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