Java: Accepts two floatingpoint numbers and checks whether they are the same up to two decimal places
Java Conditional Statement: Exercise-32 with Solution
Write a Java program that accepts two floatingpoint numbers and checks whether they are the same up to two decimal places.
Test Data
Input first floatingpoint number: 1235
Input second floatingpoint number: 2534
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise32 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Input first floatingpoint number: ");
double num1 = input.nextDouble();
System.out.print("Input second floatingpoint number: ");
double num2 = input.nextDouble();
input.close();
if (Math.abs(num1 - num2) <= 0.01) {
System.out.println("These numbers are the same.");
}
else {
System.out.println("These numbers are different.");
}
}
}
Sample Output:
Input first floatingpoint number: 1235 Input second floatingpoint number: 2534 These numbers are different.
Flowchart:

Java Code Editor:
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Previous: Write a program that accepts three numbers from the user and prints "increasing" if the numbers are in increasing order, "decreasing" if the numbers are in decreasing order, and "Neither increasing or decreasing order" otherwise.
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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