Java: Get the next floating-point adjacent in the direction of positive and negative infinity from a given float/double number

Java Data Type: Exercise-15 with Solution

Write a Java program to get the next floating-point adjacent to positive and negative infinity from a given floating/double number.

Sample Solution:

Java Code:

public class Main {
    public static void main(String[] args) {
        float fn = 0.2f;
        System.out.println("\nInitial floating number: " + fn);		
        float next_down_fn = Math.nextDown(fn);
        float next_up_fn = Math.nextUp(fn);
        System.out.println("Float " + fn + " next down is " + next_down_fn);
        System.out.println("Float " + fn + " next up is " + next_up_fn);
        double dn = 0.2d;
       System.out.println("\nInitial double number: " + dn);		
        double next_down_dn = Math.nextDown(dn);
        double next_up_dn = Math.nextUp(dn);
        System.out.println("Double " + dn + " next down is " + next_down_dn);
        System.out.println("Double " + dn + " next up is " + next_up_dn);
    }
}

Sample Output:

Initial floating number: 0.2
Float 0.2 next down is 0.19999999
Float 0.2 next up is 0.20000002

Initial double number: 0.2
Double 0.2 next down is 0.19999999999999998
Double 0.2 next up is 0.20000000000000004

Flowchart:

Java Code Editor:

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