Java: Check whether a number is an Armstrong Number or not
Java Numbers: Exercise-28 with Solution
Write a Java program to check whether a number is an Armstrong Number or not.
Armstrong (Michael F. Armstrong) number is a number that is equal to the sum of cubes of its digits. For example 0, 1, 153, 370, 371 and 407 are the Armstrong numbers
Sample Solution:
Java Code:
import java.util.*;
public class solution {
public static boolean is_Amstrong(int n) {
int remainder, sum = 0, temp = 0;
temp = n;
while (n > 0) {
remainder = n % 10;
sum = sum + (remainder * remainder * remainder);
n = n / 10;
}
return sum == temp;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Input an integer: ");
String input = scanner.nextLine();
int number = Integer.parseInt(input);
System.out.println("Is Armstrong number? "+is_Amstrong(number));
}
}
Sample Output:
Input an integer: 153 Is Armstrong number? true
Flowchart:
Java Code Editor:
Contribute your code and comments through Disqus.
Previous: Write a Java program to create the first twenty Hamming numbers.
Next: Write a Program in Java to check whether a number is a Lucky Number or not.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://www.w3resource.com/java-exercises/numbers/java-number-exercise-28.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics