w3resource

Java String Exercises: Append two given strings such that, if the concatenation creates a double characters then omit one of the characters

Java String: Exercise-56 with Solution

Write a Java program to append two given strings such that, if the concatenation creates a double characters then omit one of the characters.

Sample Solution:

Java Code:

import java.util.*;
public class Main 
{
public String conCat(String st1, String st2) 
{
        if (st1.length() != 0 && st2.length() != 0
                && st1.charAt(st1.length() - 1) == st2.charAt(0))
            return st1 + st2.substring(1);
        return st1 + st2;
}

    public static void main (String[] args)
    {
      Main m= new Main();
      String str1 =  "food";
      String str2 = "door";
      System.out.println("The given strings are: "+str1+"  and  "+str2);
      System.out.println("The string after concatination are: "+m.conCat(str1,str2));
    }
}

Sample Output:

The given strings are: food  and  door
The string after concatination are: foodoor

Pictorial Presentation:

Java String Exercises: Append two given strings such that, if the concatenation creates a double characters then omit one of the characters.

Flowchart:

Flowchart: Java String Exercises - Append two given strings such that, if the concatenation creates a double characters then omit one of the characters.

Visualize Java code execution (Python Tutor):


Java Code Editor:

Improve this sample solution and post your code through Disqus

Previous: Write a Java program to remove all adjacent duplicates recursively from a given string.
Next: Write a Java program to create a new string from a given string swapping the last two characters of the given string. The length of the given string must be two or more.

What is the difficulty level of this exercise?



Java: Tips of the Day

Array vs ArrayLists:

The main difference between these two is that an Array is of fixed size so once you have created an Array you cannot change it but the ArrayList is not of fixed size. You can create instances of ArrayLists without specifying its size. So if you create such instances of an ArrayList without specifying its size Java will create an instance of an ArrayList of default size.

Once an ArrayList is full it re-sizes itself. In fact, an ArrayList is internally supported by an array. So when an ArrayList is resized it will slow down its performance a bit as the contents of the old Array must be copied to a new Array.

At the same time, it's compulsory to specify the size of an Array directly or indirectly while creating it. And also Arrays can store both primitives and objects while ArrayLists only can store objects.

Ref: https://bit.ly/3o8L2KH