JavaScript - Check two integers have opposite signs or not

JavaScript Bit Manipulation: Exercise-1 with Solution

Write a JavaScript program to check if two given integers have opposite signs.

Test Data:
(100, -100) -> "Signs are opposite"
(100, 100) -> "Signs are not opposite"
(‘100, 100) -> "Parameters value must be number!"

Sample Solution:

JavaScript Code:

const opposite_Signs = (x, y) => {
        if ((typeof x!= "number") || (typeof y!= "number"))
        {
          return 'Parameters value must be number!'
        }  
         if ((x ^ y) < 0)
           return true; 
         else
           return false;
         }
x = 100
y = -100
result = opposite_Signs(x, y)
  if (result === true) 
      console.log("Signs are opposite"); 
  else if (result === false) 
      console.log("Signs are not opposite");
  else console.log(result);   
x = 100
y = 100
result = opposite_Signs(x, y)

  if (result === true) 
      console.log("Signs are opposite"); 
  else if (result === false) 
      console.log("Signs are not opposite");
  else console.log(result);  
x = '100'
y = 100
result = opposite_Signs(x, y)
  if (result === true) 
      console.log("Signs are opposite"); 
  else if (result === false) 
      console.log("Signs are not opposite");
  else console.log(result);

Sample Output:

Signs are opposite
Signs are not opposite
Parameters value must be number!

Flowchart:

Live Demo:

See the Pen javascript-date-exercise-54 by w3resource (@w3resource) on CodePen.

* To run the code mouse over on Result panel and click on 'RERUN' button.*

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