JavaScript - Check two integers have opposite signs or not
JavaScript Bit Manipulation: Exercise-1 with Solution
Write a JavaScript program to check if two given integers have opposite signs.
Test Data:
(100, -100) -> "Signs are opposite"
(100, 100) -> "Signs are not opposite"
(‘100, 100) -> "Parameters value must be number!"
Sample Solution:
JavaScript Code:
const opposite_Signs = (x, y) => {
if ((typeof x!= "number") || (typeof y!= "number"))
{
return 'Parameters value must be number!'
}
if ((x ^ y) < 0)
return true;
else
return false;
}
x = 100
y = -100
result = opposite_Signs(x, y)
if (result === true)
console.log("Signs are opposite");
else if (result === false)
console.log("Signs are not opposite");
else console.log(result);
x = 100
y = 100
result = opposite_Signs(x, y)
if (result === true)
console.log("Signs are opposite");
else if (result === false)
console.log("Signs are not opposite");
else console.log(result);
x = '100'
y = 100
result = opposite_Signs(x, y)
if (result === true)
console.log("Signs are opposite");
else if (result === false)
console.log("Signs are not opposite");
else console.log(result);
Sample Output:
Signs are opposite Signs are not opposite Parameters value must be number!
Flowchart:

Live Demo:
See the Pen javascript-date-exercise-54 by w3resource (@w3resource) on CodePen.
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