JavaScript - Parity of a given number
JavaScript Bit Manipulation: Exercise-13 with Solution
Write a JavaScript program to calculate and find the parity of a given number.
In mathematics, parity is the property of an integer of whether it is even or odd. In binary numbers, parity refers to the total number of 1s. The odd parity(1) represents an odd number of 1s, whereas the even parity(0) represents an even number of 1s.
In information theory, a parity bit appended to a binary number provides the simplest form of error detecting code. If a single bit in the resulting value is changed, then it will no longer have the correct parity: changing a bit in the original number gives it a different parity than the recorded one, and changing the parity bit while not changing the number it was derived from again produces an incorrect result. In this way, all single-bit transmission errors may be reliably detected. Some more sophisticated error detecting codes are also based on the use of multiple parity bits for subsets of the bits of the original encoded value.
Test Data:
(34) -> "Parity of 34 is even."
"34 in binary is 100010" // Even number of 1s
(104) -> "Parity of 104 is odd."
"104 in binary is 1101000" // Odd number of 1s
Sample Solution:
JavaScript Code:
const parity_even_odd = (n) => {
parity = false
temp = n
while (n != 0)
{
if ((n & 1) !== 0) {
parity = !parity
}
n = n >> 1
}
if (parity)
return "Parity of " +temp+ " is odd."
else
return "Parity of " +temp+ " is even."
}
n = 34
console.log(n + " in binary is " + n.toString(2))
console.log(parity_even_odd(n))
n = 104
console.log(n + " in binary is " + n.toString(2))
console.log(parity_even_odd(n))
Sample Output:
34 in binary is 100010 Parity of 34 is even. 104 in binary is 1101000 Parity of 104 is odd.
Flowchart:

Live Demo:
See the Pen javascript-bit-manipulation-exercise-12 by w3resource (@w3resource) on CodePen.
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JavaScript: Tips of the Day
Returns the sum of an array, after mapping each element to a value using the provided function
Example:
const tips_sumBy = (arr, fn) => arr.map(typeof fn === 'function' ? fn : val => val[fn]).reduce((acc, val) => acc + val, 0); console.log(tips_sumBy([{ n: 2 }, { n: 4 }, { n: 6 }, { n: 8 }], o => o.n)); console.log(tips_sumBy([{ n: 1 }, { n: 3 }, { n: 5 }, { n: 7 }], 'n'));
Output:
20 16
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