JavaScript - Find the non-repeated element from an array

JavaScript Bit Manipulation: Exercise-14 with Solution

In an array every element appears twice except for one. Write a JavaScript program to find the non-repeated element in an array using bit manipulation.

Test Data:
([1]) -> 1
([1, 2, 3]) -> 0 [All elements are non- repeated]
[1, 2, 8, 3, 1, 2, 3, 8, 6, 6, 7] -> 7

Sample Solution:

JavaScript Code:

const non_repeated_num = (nums) => {
   r = 0
   for(let i = 0; i <= nums.length; i++)
     {
       r = r ^ nums[i]
     }
   return r
 }
nums = [1, 2, 8, 3, 1, 2, 3, 8, 6, 6, 7]
console.log(non_repeated_num(nums))

Sample Output:

7

Flowchart:

Live Demo:

See the Pen javascript-bit-manipulation-exercise-14 by w3resource (@w3resource) on CodePen.

* To run the code mouse over on Result panel and click on 'RERUN' button.*

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