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JavaScript - Maximum, minimum of two integers

JavaScript Bit Manipulation: Exercise-15 with Solution

Write a JavaScript program to calculate the maximum or minimum of two integers.

Test Data:
(12, 15) -> 15, 12
(-7,-5) -> -5, -7

Sample Solution:

JavaScript Code:

 const max_min = (x, y) => {
 max = x ^ ((x ^ y) & -((x < y) ? 1 : 0))
 min = y ^ ((x ^ y) & -((x < y) ? 1 : 0));
 return {a:max, b:min}
 }
 x = 12
 y = 15
 console.log("Two numbers: " + x + "," + y)
 const {a,b} = max_min(x, y)
 console.log("Maximum value: " +a + " and Minimum value: " +b)
// x = -7
// y = -5
// console.log("Two numbers: " + x + "," + y)
// const {a,b} = max_min(x, y)
// console.log("Maximum value: " +a + " and Minimum value: " +b)

Sample Output:

Two numbers: 12,15
Maximum value: 15 and Minimum value: 12

Flowchart:

Flowchart: JavaScript - Maximum, minimum of two integers.

Live Demo:

See the Pen javascript-bit-manipulation-exercise-15 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

Returns the sum of an array, after mapping each element to a value using the provided function

Example:

const tips_sumBy = (arr, fn) =>
  arr.map(typeof fn === 'function' ? fn : val => val[fn]).reduce((acc, val) => acc + val, 0);

console.log(tips_sumBy([{ n: 2 }, { n: 4 }, { n: 6 }, { n: 8 }], o => o.n));
console.log(tips_sumBy([{ n: 1 }, { n: 3 }, { n: 5 }, { n: 7 }], 'n'));

Output:

20
16