JavaScript - Maximum, minimum of two integers
JavaScript Bit Manipulation: Exercise-15 with Solution
Write a JavaScript program to calculate the maximum or minimum of two integers.
Test Data:
(12, 15) -> 15, 12
(-7,-5) -> -5, -7
Sample Solution:
JavaScript Code:
const max_min = (x, y) => {
max = x ^ ((x ^ y) & -((x < y) ? 1 : 0))
min = y ^ ((x ^ y) & -((x < y) ? 1 : 0));
return {a:max, b:min}
}
x = 12
y = 15
console.log("Two numbers: " + x + "," + y)
const {a,b} = max_min(x, y)
console.log("Maximum value: " +a + " and Minimum value: " +b)
// x = -7
// y = -5
// console.log("Two numbers: " + x + "," + y)
// const {a,b} = max_min(x, y)
// console.log("Maximum value: " +a + " and Minimum value: " +b)
Sample Output:
Two numbers: 12,15 Maximum value: 15 and Minimum value: 12
Flowchart:

Live Demo:
See the Pen javascript-bit-manipulation-exercise-15 by w3resource (@w3resource) on CodePen.
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JavaScript: Tips of the Day
Returns the sum of an array, after mapping each element to a value using the provided function
Example:
const tips_sumBy = (arr, fn) => arr.map(typeof fn === 'function' ? fn : val => val[fn]).reduce((acc, val) => acc + val, 0); console.log(tips_sumBy([{ n: 2 }, { n: 4 }, { n: 6 }, { n: 8 }], o => o.n)); console.log(tips_sumBy([{ n: 1 }, { n: 3 }, { n: 5 }, { n: 7 }], 'n'));
Output:
20 16
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