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JavaScript - Odd or even number using bit manipulation

JavaScript Bit Manipulation: Exercise-5 with Solution

Write a JavaScript program to check a given number is odd or even using bit manipulation.

A number (i.e., integer) expressed in the decimal numeral system is even or odd according to whether its last digit is even or odd. That is, if the last digit is 1, 3, 5, 7, or 9, then it is odd; otherwise it is even-as the last digit of any even number is 0, 2, 4, 6, or 8.

Test Data:
(1) -> 1 is an odd number.
(4) -> 4 is an even number.
(9) -> 9 is an odd number.
("15") -> Parameter value must be number!

Sample Solution:

JavaScript Code:

const check_even_odd = (n) => {
        if (typeof n != "number") 
        {
          return 'Parameter value must be number!'
        }  
        if ((n ^ 1) == (n + 1))//even
           return n +' is an even number.'
        else //odd
           return n +' is an odd number.'
      }
console.log(check_even_odd(1))
console.log(check_even_odd(4))
console.log(check_even_odd(9))
console.log(check_even_odd("15"))

Sample Output:

1 is an odd number.
4 is an even number.
9 is an odd number.
Parameter value must be number!

Flowchart:

Flowchart: JavaScript - Odd or even number using bit manipulation.

Live Demo:

See the Pen javascript-bit-manipulation-exercise-5 by w3resource (@w3resource) on CodePen.


* To run the code mouse over on Result panel and click on 'RERUN' button.*

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Next: Check a number is a power of 4 or not.

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JavaScript: Tips of the Day

Creates an object composed of the properties the given function returns truthy for. The function is invoked with two arguments: (value, key)

Example:

const tips_composed = (obj, fn) =>
  Object.keys(obj)
    .filter(k => fn(obj[k], k))
    .reduce((acc, key) => ((acc[key] = obj[key]), acc), {});

console.log(tips_composed({ p: 2, q: '4', r: 6 }, x => typeof x === 'number'));

Output:

[object Object] {
  p: 2,
  r: 6
}