# JavaScript - Check a number is a power of 4 or not

## JavaScript Bit Manipulation: Exercise-6 with Solution

Write a JavaScript program to check a given positive number is a power of four or not using bit manipulation.

The expression n & (n-1) will unset the rightmost set bit of a number. If the number is a power of 2, it has only a 1-bit set, and n & (n-1) will unset the only set bit. So, we can say that n & (n-1) returns 0 if n is a power of 2; otherwise, it's not a power of 2.

The mask 0xAAAAAAAA will allow us to determine where the set bit is located. In all of its odd positions, the mask 0xAAAAAAAA has a value of 1. The set bit in n will be even if the expression (n & 0xAAAAAAAA) is true.

_{(0xAAAAAAAA)}16 = _{(10101010101010101010101010101010)}2.

**Test Data:**

(256) -> true

(4) -> true

(2) -> false

("16") -> "It must be number!"

**Sample Solution: **

**JavaScript Code:**

```
const Power_of_four = (n) => {
if (typeof n!= "number") {
return 'It must be number!'
}
return n != 0 && (n & (n - 1)) == 0 && (n & 0xAAAAAAAA) == 0;
}
console.log(Power_of_four(256))
console.log(Power_of_four(4))
console.log(Power_of_four(2))
console.log(Power_of_four("16"))
```

Sample Output:

true true false It must be number!

**Flowchart: **

**Live Demo: **

See the Pen javascript-bit-manipulation-exercise-6 by w3resource (@w3resource) on CodePen.

* To run the code mouse over on Result panel and click on 'RERUN' button.*

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## JavaScript: Tips of the Day

**Returns the symmetric difference between two arrays, after applying the provided function to each array element of both**

Example:

const tips_symmetricDifference = (x, y, fn) => { const sA = new Set(x.map(v => fn(v))), sB = new Set(y.map(v => fn(v))); return [...x.filter(x => !sB.has(fn(x))), ...y.filter(x => !sA.has(fn(x)))]; }; console.log(tips_symmetricDifference([3.5, 5.5], [5.5, 7.5], Math.floor));

Output:

[3.5, 7.5]

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