JavaScript - Turn off the kth bit of a given number
JavaScript Bit Manipulation: Exercise-9 with Solution
Write a JavaScript program to turn off the kth bit in a given number. Return the new number.
Test Data:
(30, 3)-> 26
Explanation:
Binary format of 30 is -> 11110
Fortmat of the said number after off the 3rd bit -> 11010
After converting 11010 to decimal : 11010 -> 26
(100, 6) -> 68
Explanation:
Binary format of 100 is -> 1100100
Fortmat of the said number after off the 6th bit -> 1000100
After converting 1000100 to decimal : 1000100 -> 68
Sample Solution:
JavaScript Code:
const turn_Off_Kth_Bit = (n, k) => {
if (typeof n!= "number") {
return 'It must be number!'
}
return n & ~(1 << (k - 1))
}
n = 30
k = 3
console.log(n + " in binary is " + n.toString(2))
console.log("Turning k'th bit off,"+" k = "+k);
result_n = turn_Off_Kth_Bit(n, k)
console.log(result_n + " in binary is " + result_n.toString(2))
n = 100
k = 6
console.log(n + " in binary is " + n.toString(2))
console.log("Turning k'th bit off,"+" k = "+k);
result_n = turn_Off_Kth_Bit(n, k)
console.log(result_n + " in binary is " + result_n.toString(2))
Sample Output:
30 in binary is 11110 Turning k'th bit off, k = 3 26 in binary is 11010 100 in binary is 1100100 Turning k'th bit off, k = 6 68 in binary is 1000100
Flowchart:

Live Demo:
See the Pen javascript-bit-manipulation-exercise-9 by w3resource (@w3resource) on CodePen.
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JavaScript: Tips of the Day
Returns the sum of an array, after mapping each element to a value using the provided function
Example:
const tips_sumBy = (arr, fn) => arr.map(typeof fn === 'function' ? fn : val => val[fn]).reduce((acc, val) => acc + val, 0); console.log(tips_sumBy([{ n: 2 }, { n: 4 }, { n: 6 }, { n: 8 }], o => o.n)); console.log(tips_sumBy([{ n: 1 }, { n: 3 }, { n: 5 }, { n: 7 }], 'n'));
Output:
20 16
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