JavaScript - Turn on the kth bit of a given number
JavaScript Bit Manipulation: Exercise-10 with Solution
Write a JavaScript program to turn on the kth bit in a given number. Return the new number.
Test Data:
(33, 3)-> 37
Explanation:
Binary format of 33 is -> 100001
Fortmat of the said number after on the 3rd bit -> 100101
After converting 100101 to decimal : 100101 -> 37
(101, 5) -> 117
Explanation:
Binary format of 100 is -> 1100101
Fortmat of the said number after on the 5th bit -> 1110101
After converting 1110101 to decimal : 1110101 -> 117
Sample Solution:
JavaScript Code:
const turn_On_Kth_Bit = (n, k) => {
if (typeof n!= "number") {
return 'It must be number!'
}
return n | (1 << (k - 1));
}
n = 33
k = 3
console.log(n + " in binary is " + n.toString(2))
console.log("Turning k'th bit on,"+" k = "+k);
result_n = turn_On_Kth_Bit(n, k);
console.log(result_n + " in binary is " + result_n.toString(2))
n = 101
k = 5
console.log(n + " in binary is " + n.toString(2))
console.log("Turning k'th bit on,"+" k = "+k);
result_n = turn_On_Kth_Bit(n, k);
console.log(result_n + " in binary is " + result_n.toString(2))
Sample Output:
33 in binary is 100001 Turning k'th bit on, k = 3 37 in binary is 100101 101 in binary is 1100101 Turning k'th bit on, k = 5 117 in binary is 1110101
Flowchart:

Live Demo:
See the Pen javascript-bit-manipulation-exercise-10 by w3resource (@w3resource) on CodePen.
* To run the code mouse over on Result panel and click on 'RERUN' button.*
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JavaScript: Tips of the Day
Creates an object composed of the properties the given function returns truthy for. The function is invoked with two arguments: (value, key)
Example:
const tips_composed = (obj, fn) => Object.keys(obj) .filter(k => fn(obj[k], k)) .reduce((acc, key) => ((acc[key] = obj[key]), acc), {}); console.log(tips_composed({ p: 2, q: '4', r: 6 }, x => typeof x === 'number'));
Output:
[object Object] { p: 2, r: 6 }
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