JavaScript: Get all unique values (form the right side of the array) of an array, based on a provided comparator function

JavaScript fundamental (ES6 Syntax): Exercise-107 with Solution

Write a JavaScript program to get all distinct values (from the right side of the array) of an array, based on a provided comparator function.

• Use Array.prototype.reduceRight() and Array.prototype.some() for an array containing only the last unique occurrence of each value, based on the comparator function, fn.
• The comparator function takes two arguments: the values of the two elements being compared.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const uniqueElementsByRight = (arr, fn) =>
  arr.reduceRight((acc, v) => {
    if (!acc.some(x => fn(v, x))) acc.push(v);
    return acc;
  }, []);

console.log(uniqueElementsByRight(
  [
    { id: 0, value: 'a' },
    { id: 1, value: 'b' },
    { id: 2, value: 'c' },
    { id: 1, value: 'd' },
    { id: 0, value: 'e' }
  ],
  (a, b) => a.id == b.id
));

Sample Output:

[{"id":0,"value":"e"},{"id":1,"value":"d"},{"id":2,"value":"c"}]

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-107-1 by w3resource (@w3resource) on CodePen.

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