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JavaScript : Create a function that invokes the provided function with its arguments transformed

JavaScript fundamental (ES6 Syntax): Exercise-172 with Solution

Write a JavaScript program to create a function that invokes the provided function with its arguments transformed.

  • Use Array.prototype.map() to apply transforms to args in combination with the spread operator (...) to pass the transformed arguments to fn.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const overArgs = (fn, transforms) => (...args) => fn(...args.map((val, i) => transforms[i](val)));
const square = n => n * n;
const double = n => n * 2;
const fn = overArgs((x, y) => [x, y], [square, double]);
console.log(fn(9,3));
console.log(fn(5,2));

Sample Output:

[81,6]
[25,4]

Pictorial Presentation:

JavaScript Fundamental: Create a function that invokes the provided function with its arguments transformed.
JavaScript Fundamental: Create a function that invokes the provided function with its arguments transformed.

Flowchart:

flowchart: Create a function that invokes the provided function with its arguments transformed

Live Demo:

See the Pen javascript-basic-exercise-172-1 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

How to check whether a string contains a substring in JavaScript?

ECMAScript 6 introduced String.prototype.includes:

const string = "foo";
const substring = "oo";

console.log(string.includes(substring));

includes doesn't have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:

var string = "foo";
var substring = "oo";

console.log(string.indexOf(substring) !== -1);

Ref: https://bit.ly/3fFFgZv