JavaScript: Get a list of elements that exist in both arrays
JavaScript fundamental (ES6 Syntax): Exercise-211 with Solution
Write a JavaScript program to get a list of elements that exist in both arrays.
- Create a Set from b, then use Array.prototype.filter() on a to only keep values contained in b.
Sample Solution:
JavaScript Code:
//#Source https://bit.ly/2neWfJ2
const intersection = (a, b) => {
const s = new Set(b);
return a.filter(x => s.has(x));
};
console.log(intersection([1, 2, 3], [4, 3, 2]));
Sample Output:
[2,3]
Pictorial Presentation:
Flowchart:

Live Demo:
See the Pen javascript-basic-exercise-211-1 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to get a list of elements that exist in both arrays, after applying the provided function to each array element of both.
Next: Write a JavaScript program to create a n-dimensional array with given value.
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JavaScript: Tips of the Day
How to check whether a string contains a substring in JavaScript?
ECMAScript 6 introduced String.prototype.includes:
const string = "foo"; const substring = "oo"; console.log(string.includes(substring));
includes doesn't have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:
var string = "foo"; var substring = "oo"; console.log(string.indexOf(substring) !== -1);
Ref: https://bit.ly/3fFFgZv
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