# JavaScript: Return true if the string is y/yes other wise false

## JavaScript fundamental (ES6 Syntax): Exercise-26 with Solution

Write a JavaScript program that will return true if the string is y/yes or false if the string is n/no.

• Use RegExp.prototype.test() to check if the string evaluates to y/yes or n/no.
• Omit the second argument, def to set the default answer as no.

Sample Solution:

JavaScript Code:

``````//#Source https://bit.ly/2neWfJ2
const yes_No = (val, def = false) =>
/^(y|yes)\$/i.test(val) ? true : /^(n|no)\$/i.test(val) ? false : def;
console.log(yes_No('Y'));
console.log(yes_No('yes'));
console.log(yes_No('No'));
console.log(yes_No('Foo', true));
```
```

Note: Omit the second argument, def to set the default answer as no.

Sample Output:

```true
true
false
true
```

Pictorial Presentation:

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-1-26 by w3resource (@w3resource) on CodePen.

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## JavaScript: Tips of the Day

Returns an array of n-tuples of consecutive elements

Example:

```const tips_arr = (n, arr) =>  n > arr.length ? [] : arr.slice(n - 1).map((v, i) =>[...arr.slice(i, i + n - 1), v]);
console.log(tips_arr(2, [1, 2, 3, 4, 5]));
console.log(tips_arr(3, [1, 2, 3, 4, 5]));
console.log(tips_arr(5, [1, 2, 3, 4]));
```

Output:

```[[1, 2], [2, 3], [3, 4], [4, 5]]
[[1, 2, 3], [2, 3, 4], [3, 4, 5]]
[]
```