- Use RegExp.prototype.test() to check if the string evaluates to y/yes or n/no.
- Omit the second argument, def to set the default answer as no.
//#Source https://bit.ly/2neWfJ2 const yes_No = (val, def = false) => /^(y|yes)$/i.test(val) ? true : /^(n|no)$/i.test(val) ? false : def; console.log(yes_No('Y')); console.log(yes_No('yes')); console.log(yes_No('No')); console.log(yes_No('Foo', true));
Note: Omit the second argument, def to set the default answer as no.
true true false true
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