JavaScript fundamental: Get a sorted array of objects ordered by properties and orders

JavaScript fundamental (ES6 Syntax): Exercise-37 with Solution

Write a JavaScript program to get a sorted array of objects ordered by properties and orders.

• Uses Array.prototype.sort(), Array.prototype.reduce() on the props array with a default value of 0.
• Use array destructuring to swap the properties position depending on the order supplied.
• If no orders array is supplied, sort by 'asc' by default.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const orderBy = (arr, props, orders) =>
  [...arr].sort((a, b) =>
    props.reduce((acc, prop, i) => {
      if (acc === 0) {
        const [p1, p2] = orders && orders[i] === 'desc' ? [b[prop], a[prop]] : [a[prop], b[prop]];
        acc = p1 > p2 ? 1 : p1 < p2 ? -1 : 0;
      }
      return acc;
    }, 0)
  );
const users = [{ name: 'fred', age: 48 }, { name: 'barney', age: 36 }, { name: 'fred', age: 40 }];

console.log(orderBy(users, ['name', 'age'], ['asc', 'desc'])); 
console.log(orderBy(users, ['name', 'age']));

Sample Output:

[{"name":"barney","age":36},{"name":"fred","age":48},{"name":"fred","age":40}]
[{"name":"barney","age":36},{"name":"fred","age":40},{"name":"fred","age":48}]

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-1-37 by w3resource (@w3resource) on CodePen.

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