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JavaScript: Accepts a converging function and a list of branching functions

JavaScript fundamental (ES6 Syntax): Exercise-68 with Solution

Write a JavaScript program that accepts a converging function and a list of branching functions and returns a function that applies each branching function to the arguments and the results of the branching functions are passed as arguments to the converging function.

  • Use Array.prototype.map() and Function.prototype.apply() to apply each function to the given arguments.
  • Use the spread operator (...) to call converger with the results of all other functions.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const converge = (converger, fns) => (...args) => converger(...fns.map(fn => fn.apply(null, args)));
const average = converge((a, b) => a / b, [
  arr => arr.reduce((a, v) => a + v, 0),
  arr => arr.length
]);
console.log(average([ 6, 7]));
console.log(average([1, 2, 3, 4, 5, 6, 7]));

Sample Output:

6.5
4

Pictorial Presentation:

JavaScript Fundamental: Accepts a converging function and a list of branching functions
JavaScript Fundamental: Accepts a converging function and a list of branching functions

Flowchart:

flowchart: Accepts a converging function and a list of branching functions

Live Demo:

See the Pen javascript-basic-exercise-68-1 by w3resource (@w3resource) on CodePen.


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Next: Write a JavaScript program to group the elements of an array based on the given function and returns the count of elements in each group.

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JavaScript: Tips of the Day

Returns the unique symmetric difference between two arrays, not containing duplicate values from either array

Example:

const uniqueSymmetricDifference = (a, b) => [
  ...new Set([...a.filter(v => !b.includes(v)), ...b.filter(v => !a.includes(v))])
];
console.log(uniqueSymmetricDifference([1, 2, 3], [1, 2, 4])); // [3, 4]
console.log(uniqueSymmetricDifference([1, 2, 2], [1, 3, 1])); // [2, 3]

Output:

[3, 4]
[2, 3]