JavaScript: Accepts a converging function and a list of branching functions
JavaScript fundamental (ES6 Syntax): Exercise-68 with Solution
Write a JavaScript program that accepts a converging function and a list of branching functions and returns a function that applies each branching function to the arguments and the results of the branching functions are passed as arguments to the converging function.
- Use Array.prototype.map() and Function.prototype.apply() to apply each function to the given arguments.
- Use the spread operator (...) to call converger with the results of all other functions.
Sample Solution:
JavaScript Code:
//#Source https://bit.ly/2neWfJ2
const converge = (converger, fns) => (...args) => converger(...fns.map(fn => fn.apply(null, args)));
const average = converge((a, b) => a / b, [
arr => arr.reduce((a, v) => a + v, 0),
arr => arr.length
]);
console.log(average([ 6, 7]));
console.log(average([1, 2, 3, 4, 5, 6, 7]));
Sample Output:
6.5 4
Pictorial Presentation:
Flowchart:

Live Demo:
See the Pen javascript-basic-exercise-68-1 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to perform left-to-right function composition.
Next: Write a JavaScript program to group the elements of an array based on the given function and returns the count of elements in each group.
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JavaScript: Tips of the Day
Returns the unique symmetric difference between two arrays, not containing duplicate values from either array
Example:
const uniqueSymmetricDifference = (a, b) => [ ...new Set([...a.filter(v => !b.includes(v)), ...b.filter(v => !a.includes(v))]) ]; console.log(uniqueSymmetricDifference([1, 2, 3], [1, 2, 4])); // [3, 4] console.log(uniqueSymmetricDifference([1, 2, 2], [1, 3, 1])); // [2, 3]
Output:
[3, 4] [2, 3]
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