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JavaScript: Find the maximum number from a given positive integer by deleting exactly one digit of the given number

JavaScript Basic: Exercise-103 with Solution

Write a JavaScript program to find the maximum number from a given positive integer by deleting exactly one digit of the given number.

Pictorial Presentation:

JavaScript: Find the maximum number from a given positive integer by deleting exactly one digit of the given number.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title> Find the maximum number from a given positive integer by deleting exactly one digit of the given number</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function digit_delete(num) {
    var result = 0,
        num_digits = [];
    while (num) {
        num_digits.push(num % 10);
        num = Math.floor(num / 10);
    }
    for (var index_num = 0; index_num < num_digits.length; index_num++) {
        var n = 0;
        for (var i = num_digits.length - 1; i >= 0; i--) {
            if (i !== index_num) {
                n = n * 10 + num_digits[i];
            }
        }
        result = Math.max(n, result);
    }
    return result;
}

console.log(digit_delete(100));
console.log(digit_delete(10));
console.log(digit_delete(1245)); 

Sample Output:

10
1
245

Flowchart:

Flowchart: JavaScript - Find the maximum number from a given positive integer by deleting exactly one digit of the given number

ES6 Version:

function digit_delete(num) {
    let result = 0;
    const num_digits = [];
    while (num) {
        num_digits.push(num % 10);
        num = Math.floor(num / 10);
    }
    for (let index_num = 0; index_num < num_digits.length; index_num++) {
        let n = 0;
        for (let i = num_digits.length - 1; i >= 0; i--) {
            if (i !== index_num) {
                n = n * 10 + num_digits[i];
            }
        }
        result = Math.max(n, result);
    }
    return result;
}

console.log(digit_delete(100));
console.log(digit_delete(10));
console.log(digit_delete(1245));

Live Demo:

See the Pen javascript-basic-exercise-103 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to find the number of inversions of a given array of integers.
Next: Write a JavaScript program to find two elements of the array such that their absolute difference is not greater than a given integer but is as close to the said integer.

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JavaScript: Tips of the Day

Promise object

const myPromise = () => Promise.resolve('I have resolved!');

function firstFunction() {
  myPromise().then(res => console.log(res));
  console.log('second');
}

async function secondFunction() {
  console.log(await myPromise());
  console.log('second');
}

firstFunction();
secondFunction();

With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then and the await keyword in an async function. Although we can get a promise's value with both .then and await, they work a bit differently.
In the firstFunction, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second') in this case. Then, the function resolved with the string I have resolved, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise to resolve with the value I have resolved, and only once that happened, we moved to the next line: second got logged.

Ref: https://bit.ly/3jFRBje