JavaScript: Find two elements of the array such that their absolute difference is not greater than a given integer but is as close to the said integer

JavaScript Basic: Exercise-104 with Solution

Find Pair with Closest Absolute Difference

Write a JavaScript program to find two elements of an array such that their absolute difference is not larger than a given integer. However, it is as close as possible to the integer.

Sample Solution:

JavaScript Code:

// Function to find the maximum absolute difference between elements of an array that is less than or equal to a given number
function different_values(ara, n) {
    var max_val = -1; // Initializing the maximum value as -1
    for (var i = 0; i < ara.length; i++) { // Looping through the array elements
        for (var j = i + 1; j < ara.length; j++) { // Nested loop for comparisons with subsequent elements
            var x = Math.abs(ara[i] - ara[j]); // Calculating the absolute difference between elements
            if (x <= n) { // Checking if the absolute difference is less than or equal to 'n'
                max_val = Math.max(max_val, x); // Updating the maximum value if the condition is met
            }
        }
    }
    return max_val; // Returning the maximum value found
}

// Examples of using the function with different arrays and values of 'n'
console.log(different_values([12, 10, 33, 34], 10)); // Example usage
console.log(different_values([12, 10, 33, 34], 24)); // Example usage
console.log(different_values([12, 10, 33, 44], 40)); // Example usage 

Output:

2
24
34

Live Demo:

See the Pen javascript-basic-exercise-104 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// Function to find the maximum difference between two array elements that are less than or equal to a given number
const different_values = (ara, n) => {
    let max_val = -1; // Initialize maximum difference variable to track the result
    for (let i = 0; i < ara.length; i++) { // Loop through the array elements
        for (let j = i + 1; j < ara.length; j++) { // Loop through subsequent elements to compare differences
            let x = Math.abs(ara[i] - ara[j]); // Calculate the absolute difference between array elements
            if (x <= n) { // Check if the difference is less than or equal to the given number
                max_val = Math.max(max_val, x); // Update the maximum difference if the current difference is greater
            }
        }
    }
    return max_val; // Return the maximum difference found
}

// Example usage of the function
console.log(different_values([12, 10, 33, 34], 10));
console.log(different_values([12, 10, 33, 34], 24));
console.log(different_values([12, 10, 33, 44], 40));

For more Practice: Solve these Related Problems:

• Write a JavaScript program that finds two elements in an array whose absolute difference is as close as possible to a given target without exceeding it.
• Write a JavaScript function that sorts an array and then identifies the pair with the absolute difference nearest to a specified threshold.
• Write a JavaScript program that iterates through all pairs in a sorted array to return the one with the minimal difference compared to a given value.

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