JavaScript: Find whether the members of a given array of integers is a permutation of numbers from 1 to a given integer
JavaScript Basic: Exercise-123 with Solution
Write a JavaScript program to find whether the members of a given array of integers is a permutation of numbers from 1 to a given integer.
Pictorial Presentation:

Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title> Find whether the members of a given array of integers is a permutation of numbers from 1 to a given integer</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function is_permutation(input_arr, n) {
for (var i = 0; i < n; i++) {
if (input_arr.indexOf(i + 1) < 0)
return false;
}
return true;
}
console.log(is_permutation([1, 2, 3, 4, 5], 5));
console.log(is_permutation([1, 2, 3, 5], 5));
Sample Output:
true false
Flowchart:

ES6 Version:
function is_permutation(input_arr, n) {
for (let i = 0; i < n; i++) {
if (!input_arr.includes(i + 1))
return false;
}
return true;
}
console.log(is_permutation([1, 2, 3, 4, 5], 5));
console.log(is_permutation([1, 2, 3, 5], 5));
Live Demo:
See the Pen javascript-basic-exercise-123 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to check whether a given array of integers represents either a strictly increasing or a strictly decreasing sequence.
Next: Write a JavaScript program to create the value of NOR of two given booleans.
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JavaScript: Tips of the Day
Returns the sum of the powers of all the numbers from start to end (both inclusive)
Example:
const sumPower = (end, power = 2, start = 1) => Array(end + 1 - start) .fill(0) .map((x, i) => (i + start) ** power) .reduce((a, b) => a + b, 0); console.log(sumPower(10)); // 385 console.log(sumPower(10, 3)); // 3025 console.log(sumPower(10, 3, 5)); // 2925
Output:
385 3025 2925
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