w3resource

JavaScript: Reverse the order of the bits in a given integer

JavaScript Basic: Exercise-127 with Solution

Write a JavaScript program to reverse the order of the bits in a given integer.

56 -> 111000 after reverse 7 -> 111
234 -> 11101010 after reverse 87 -> 1010111

Pictorial Presentation:

JavaScript: Reverse the order of the bits in a given integer.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title> Reverse the order of the bits in a given integer</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function mirror_bits(n) {
  return parseInt(n.toString(2).split("").reverse().join(""), 2);
}

console.log(mirror_bits(56));
console.log(mirror_bits(234));

Sample Output:

7
87

Flowchart:

Flowchart: JavaScript - Reverse the order of the bits in a given integer

ES6 Version:

function mirror_bits(n) {
  return parseInt(n.toString(2).split("").reverse().join(""), 2);
}

console.log(mirror_bits(56));
console.log(mirror_bits(234));

Live Demo:

See the Pen javascript-basic-exercise-127 by w3resource (@w3resource) on CodePen.


Improve this sample solution and post your code through Disqus

Previous: Write a JavaScript program to get the largest even number from an array of integers.
Next: Write a JavaScript program to find the smallest round number that is not less than a given value.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Share this Tutorial / Exercise on : Facebook and Twitter

JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925