 # JavaScript: Check whether a given positive number is a multiple of 3 or a multiple of 7

## JavaScript Basic: Exercise-25 with Solution

Write a JavaScript program to check whether a given positive number is a multiple of 3 or a multiple of 7.

Pictorial Presentation: Sample Solution:

HTML Code:

``````<!DOCTYPE html>
<html>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JavaScript program to check whether a given positive number is a multiple of 3 or a multiple of 7. </title>
<body>

</body>
</html>
```
```

JavaScript Code:

``````function test37(x)
{
if (x % 3 == 0 || x % 7 == 0)
{
return true;
}
else {
return false;
}
}

console.log(test37(12));
console.log(test37(14));
console.log(test37(10));
console.log(test37(11));
```
```

Sample Output:

```true
true
false
false
```

Flowchart: ES6 Version:

``````function test37(x)
{
if (x % 3 == 0 || x % 7 == 0)
{
return true;
}
else {
return false;
}
}

console.log(test37(12));
console.log(test37(14));
console.log(test37(10));
console.log(test37(11));
``````

Live Demo:

See the Pen JavaScript: check if a given positive number is a multiple of 3 or 7.-basic-ex-25 by w3resource (@w3resource) on CodePen.

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﻿

## JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

```const sumPower = (end, power = 2, start = 1) =>
Array(end + 1 - start)
.fill(0)
.map((x, i) => (i + start) ** power)
.reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925
```

Output:

```385
3025
2925
```