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JavaScript: Check whether a string "Script" presents at 5th (index 4) position in a given string

JavaScript Basic: Exercise-30 with Solution

Write a JavaScript program to check whether a string "Script" presents at 5th (index 4) position in a given string, if "Script" presents in the string return the string without "Script" otherwise return the original one.

Pictorial Presentation:

JavaScript: Check whether a string 'Script' presents at 5th (index 4) position in a given string

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to check whether a string “Script” presents at 5th (index 4) position in a given string, if “Script” presents in the string return the string without “Script” otherwise return the original one.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function check_script(str)
{
  if (str.length < 6) {
    return str;
  }
  let result_str = str;
    
  if (str.substring(10, 4) == 'Script') 
    {
    
   result_str = str.substring(0, 4) + str.substring(10,str.length);
      
  }
  return result_str;
}

console.log(check_script("JavaScript"));
console.log(check_script("CoffeeScript"));

Sample Output:

Java
CoffeeScript

Flowchart:

Flowchart: JavaScript - Check whether a string

ES6 Version:

function check_script(str)
{
  if (str.length < 6) {
    return str;
  }
  let result_str = str;
    
  if (str.substring(10, 4) == 'Script') 
    {
    
   result_str = str.substring(0, 4) + str.substring(10,str.length);
      
  }
  return result_str;
}

console.log(check_script("JavaScript"));
console.log(check_script("CoffeeScript"));

Live Demo:

See the Pen JavaScript: check if a string Script presents at 5th position - ex-30 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925