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JavaScript: Move last three character to the start of a specified string

JavaScript Basic: Exercise-62 with Solution

Write a JavaScript program to move last three character to the start of a given string. The string length must be greater or equal to three.

Pictorial Presentation:

JavaScript: Move last three character to the start of a specified string

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to move last three character to the start of a given string. The string length must be 3.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function right_three(str) {
     if (str.length > 1)
       {
         return str.slice(-3) + str.slice(0, -3);
       }
  return str;
}
console.log(right_three("Python"));
console.log(right_three("JavaScript"));
console.log(right_three("Hi"));

Sample Output:

honPyt
iptJavaScr
Hi

Flowchart:

Flowchart: JavaScript - Move last three character to the start of a specified string

ES6 Version:

function right_three(str) {
     if (str.length > 1)
       {
         return str.slice(-3) + str.slice(0, -3);
       }
  return str;
}
console.log(right_three("Python"));
console.log(right_three("JavaScript"));
console.log(right_three("Hi"));

Live Demo:

See the Pen JavaScript - Move last three character to the start of a specified string - basic-ex-62 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to concatenate two strings except their first character.
Next: Write a JavaScript program to create a string using the middle three characters of a given string of odd length.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925

Output:

385
3025
2925