JavaScript: Reverse the elements of a given array of integers length 3
JavaScript Basic: Exercise-73 with Solution
Write a JavaScript program to reverse the elements of a given array of integers length 3.
Pictorial Presentation:

Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JavaScript program to reverse the elements of a given array of integers length 3.</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function reverse3(array) {
return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}
console.log(reverse3([5, 4, 3]));
console.log(reverse3([1, 0, -1]));
console.log(reverse3([2, 3, 1]));
Sample Output:
[3,4,5] [-1,0,1] [1,3,2]
Flowchart:

ES6 Version:
function reverse3(array) {
return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}
console.log(reverse3([5, 4, 3]));
console.log(reverse3([1, 0, -1]));
console.log(reverse3([2, 3, 1]));
Live Demo:
See the Pen JavaScript - Reverse the elements of a given array of integers length 3 - basic-ex-73 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to check if the first and last elements are equal of a given array of integers length 3.
Next: Write a JavaScript program to find the larger value between the first or last and set all the other elements with that value.
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JavaScript: Tips of the Day
Returns the sum of the powers of all the numbers from start to end (both inclusive)
Example:
const sumPower = (end, power = 2, start = 1) => Array(end + 1 - start) .fill(0) .map((x, i) => (i + start) ** power) .reduce((a, b) => a + b, 0); console.log(sumPower(10)); // 385 console.log(sumPower(10, 3)); // 3025 console.log(sumPower(10, 3, 5)); // 2925
Output:
385 3025 2925
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