 # JavaScript: Reverse the elements of a given array of integers length 3

## JavaScript Basic: Exercise-73 with Solution

Write a JavaScript program to reverse the elements of a given array of integers length 3.

Pictorial Presentation: Sample Solution:

HTML Code:

``````<!DOCTYPE html>
<html>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JavaScript program to reverse the elements of a given array of integers length 3.</title>
<body>

</body>
</html>
```
```

JavaScript Code:

``````function reverse3(array) {
return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}

console.log(reverse3([5, 4, 3]));
console.log(reverse3([1, 0, -1]));
console.log(reverse3([2, 3, 1]));
```
```

Sample Output:

```[3,4,5]
[-1,0,1]
[1,3,2]
```

Flowchart: ES6 Version:

``````function reverse3(array) {
return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}

console.log(reverse3([5, 4, 3]));
console.log(reverse3([1, 0, -1]));
console.log(reverse3([2, 3, 1]));
``````

Live Demo:

See the Pen JavaScript - Reverse the elements of a given array of integers length 3 - basic-ex-73 by w3resource (@w3resource) on CodePen.

What is the difficulty level of this exercise?

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## JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

```const sumPower = (end, power = 2, start = 1) =>
Array(end + 1 - start)
.fill(0)
.map((x, i) => (i + start) ** power)
.reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925
```

Output:

```385
3025
2925
```