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JavaScript: Reverse the elements of a given array of integers length 3

JavaScript Basic: Exercise-73 with Solution

Write a JavaScript program to reverse the elements of a given array of integers length 3.

Pictorial Presentation:

JavaScript: Reverse the elements of a given array of integers length 3.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to reverse the elements of a given array of integers length 3.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function reverse3(array) {
    return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}

console.log(reverse3([5, 4, 3])); 
console.log(reverse3([1, 0, -1]));  
console.log(reverse3([2, 3, 1]));

Sample Output:

[3,4,5]
[-1,0,1]
[1,3,2]

Flowchart:

Flowchart: JavaScript - Reverse the elements of a given array of integers length 3

ES6 Version:

function reverse3(array) {
    return array.map((element, idx, arr) => arr[(arr.length - 1) - idx]);
}

console.log(reverse3([5, 4, 3])); 
console.log(reverse3([1, 0, -1]));  
console.log(reverse3([2, 3, 1]));

Live Demo:

See the Pen JavaScript - Reverse the elements of a given array of integers length 3 - basic-ex-73 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to check if the first and last elements are equal of a given array of integers length 3.
Next: Write a JavaScript program to find the larger value between the first or last and set all the other elements with that value.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925

Output:

385
3025
2925