JavaScript: Test whether an array of integers of length 2 does not contain 1 or a 3

JavaScript Basic: Exercise-78 with Solution

Check if Array Does Not Contain 1 or 3

Write a JavaScript program to test whether an array of integers of length 2 does not contain 1 or 3.

Visual Presentation:

Sample Solution:

JavaScript Code:

// Function checks if the array does not contain the values 1 or 3
function is13(nums) {
  // Check if index of 1 is -1 (not found) and index of 3 is -1 (not found)
  if (nums.indexOf(1) == -1 && nums.indexOf(3) == -1) {
    // If both values are not found, return true
    return true;
  } else {
    // If at least one of the values is found, return false
    return false;
  }
}

// Example usage
console.log(is13([7, 8]));  // true, as neither 1 nor 3 is present
console.log(is13([3, 2]));  // false, as 3 is present
console.log(is13([0, 1]));  // false, as 1 is present

Output:

true
false
false

Live Demo:

See the Pen JavaScript - Test whether an array of integers of length 2 does not contain 1 or a 3-basic-ex-78 by w3resource (@w3resource) on CodePen.

Flowchart:

ES6 Version:

// ES6 version using arrow function
const is13 = (nums) => {
  return nums.indexOf(1) === -1 && nums.indexOf(3) === -1;
};

// Example usage
console.log(is13([7, 8]));
console.log(is13([3, 2]));
console.log(is13([0, 1]));

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