JavaScript: Test whether a given array of integers contains 30 or 40 twice
JavaScript Basic: Exercise-79 with Solution
Write a JavaScript program to test whether a given array of integers contains 30 or 40 twice. The array length should be 0, 1, or 2.
Pictorial Presentation:

Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JavaScript program to test whether a given array of integers contains 30 or 40 twice. The array length should be 0, 1, or 2.</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function twice3040(arra1) {
let a = arra1[0],
b = arra1[1];
return (a === 30 && b === 30) || (a === 40 && b === 40);
}
console.log(twice3040([30, 30]));
console.log(twice3040([40, 40]));
console.log(twice3040([20, 20]));
console.log(twice3040([30]));
Sample Output:
true true false true
Flowchart:

ES6 Version:
function twice3040(arra1) {
let a = arra1[0];
let b = arra1[1];
return (a === 30 && b === 30) || (a === 40 && b === 40);
}
console.log(twice3040([30, 30]));
console.log(twice3040([40, 40]));
console.log(twice3040([20, 20]));
console.log(twice3040([30]));
Live Demo:
See the Pen JavaScript - Test whether an array of integers of length 2 does not contain 1 or a 3-basic-ex-78 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to test whether an array of integers of length 2 does not contain 1 or a 3.
Next: Write a JavaScript program to swap the first and last elements of a given array of integers. The array length should be at least 1.
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JavaScript: Tips of the Day
Returns the sum of the powers of all the numbers from start to end (both inclusive)
Example:
const sumPower = (end, power = 2, start = 1) => Array(end + 1 - start) .fill(0) .map((x, i) => (i + start) ** power) .reduce((a, b) => a + b, 0); console.log(sumPower(10)); // 385 console.log(sumPower(10, 3)); // 3025 console.log(sumPower(10, 3, 5)); // 2925
Output:
385 3025 2925
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